\overline{X}_n\equiv\frac{1}{n}\sum^n_{i=1}X_i, \quad \tilde{\sigma}^2_n\equiv\frac{1}{n-1}\sum^n_{i=1}(X_i - \overline{X}_n)^2\\
T_s\equiv\displaystyle\frac{\sqrt{n}(\overline{X}_n - \mu)}{\tilde{\sigma}_n}  \\
Embed the image to your blog in HTML, Markdown, Textile, BBCode.
Recent Referers:
  1. http://formula.s21g.com/?%5Coverline%7BX%7D_n%5Cequiv%5Cf...
  2. http://formula.s21g.com/?%5Coverline%7BX%7D_n%5Cequiv%5Cf...
  3. https://aaaazzzz036.hatenablog.com/entry/2013/05/31/19555...
  4. https://aaaazzzz036.hatenablog.com/entry/2013/05/31/19555...
  5. https://aaaazzzz036.hatenablog.com/entry/2013/05/31/19555...