(B^*A^*)_{ij} = \sum_{k} B^*_{ik} A^*_{kj} = \sum_{k} \overline{B}_{ki} \overline{A}_{jk} = \sum_{k} \overline{A}_{jk} \overline{B}_{ki}
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  2. http://techtipshoge.blogspot.com/2013/11/conjugate-transp...
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