formula

$E[V]&=&\int_{\mathbf{R}}\exp(M|x|)\frac{1}{\sqrt{2\pi t}}\exp(-\frac{x^2}{2t})dx+1\\ &\leq&2\int_{\mathbf{R}}\exp(Mx)\frac{1}{\sqrt{2\pi t}}\exp(-\frac{x^2}{2t})dx +1\\ &=&\exp\bigg(\frac{M^2t}{2}\bigg) +1<\infty$