P_n(x)&=&(x-x_0)(x-x_1)\cdots(x-x_n)
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  1. http://formula.s21g.com/?P_n(x)%26%3D%26(x-x_0)(x-x_1)%5C...
  2. https://aaaazzzz036.hatenablog.com/
  3. http://formula.s21g.com/
  4. http://aaaazzzz036.hatenablog.com/?page=1352555190