I(p)=\bigcup_{x \in X}^{} I_x(p)
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Recent Referers:
  1. http://commu-zatsu.hatenablog.com/entry/2017/04/23/152513
  2. http://commu-zatsu.hatenablog.com/
  3. http://blog.hatena.ne.jp/commu_zatsu/commu-zatsu.hatenabl...