T[y]=\int^{400km}_{0km}\sqrt{\frac{1+y'^2}{2gy}}dx\\
=\int^{2\pi}_{0}\sqrt{\frac{1+(\frac{dy}{d\theta}/\frac{dx}{d\theta})^2}{2gy(\theta)}}\frac{dx}{d\theta}d\theta\\
=\sqrt{\frac{A}{g}}2\pi
Embed the image to your blog in HTML, Markdown, Textile, BBCode.
Recent Referers:
  1. http://formula.s21g.com/formulae/46385
  2. http://formula.s21g.com/?T[y]%3D%5Cint%5E%7B400km%7D_%7B0...