\lim_{n \to \infty}P\left(\displaystyle\frac{\sqrt{n}\left(\overline{X}_n - \mu\right)}{\sigma}\le x\right)=\Phi(x)\\
\overline{X}_n=\frac{1}{n}\sum_{i=1}^nX_i\\
\displaystyle\frac{\sqrt{n}\left(\overline{X}_n - \mu\right)}{\sigma}\stackrel{\L}{\longrightarrow}Z\sim N(0, 1)
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