\sum_{n\neq a} p_n\frac{p_a}{1-p_n}=p_b\frac{p_a}{1-p_b}+p_c\frac{p_a}{1-p_c}+p_d\frac{p_d}{1-p_n}+p_n\frac{p_e}{1-p_n}
Embed the image to your blog in HTML, Markdown, Textile, BBCode.
Recent Referers:
  1. http://blog.goo.ne.jp/admin.php?fid=newentry