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n,m
\sum_{k=1}^n \prod_{l=1}^m (k+l-1)=\frac{1}{m+1}\prod_{l=1}^{m+1}(n+l-1)
Adenin
\purinev{4==NH$\mathrm{_2}$;6==H;2==H;1==H}

f(x)=\frac{1}{x}
\prod_{k=0}^{n-1}F_k=F_n-2\ \ \ (n\ge1)