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\sum_{nneq a} p_n\frac{p_a}{1-p_n}=p_b\frac{p_a}{1-p_b}+p_c\frac{p_a}{1-p_c}+p_d\frac{p_a}{1-p_d}+p_efrac{p_a}{1-p_e}
\sum_{nneq a} p_n\frac{p_a}{1-p_n}=p_b\frac{p_a}{1-p_b}+p_c\frac{p_a}{1-p_c}+p_dfrac{p_a}{1-p_d}+p_efrac{p_a}{1-p_e}
\sum_{nneq a} p_n\frac{p_a}{1-p_n}=p_b\frac{p_a}{1-p_b}+p_cfrac{p_a}{1-p_c}+p_dfrac{p_a}{1-p_d}+p_efrac{p_a}{1-p_e}
\sum_{nneq a} p_n\frac{p_a}{1-p_n}=p_bfrac{p_a}{1-p_b}+p_cfrac{p_a}{1-p_c}+p_dfrac{p_a}{1-p_d}+p_efrac{p_a}{1-p_e}
\sum_{nneq a} p_nfrac{p_a}{1-p_n}=p_bfrac{p_a}{1-p_b}+p_cfrac{p_a}{1-p_c}+p_dfrac{p_a}{1-p_d}+p_efrac{p_a}{1-p_e}