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Recently Referred Formulae

\ddot{a}_{\overline{n}|}=(1+i)a_{\overline{n}|}-1
a_{\overline{n}|}=\ddot{a}_{\overline{n+1}|}-1
\ddot{s}_{\overline{n}|}=(1+i)s_{\overline{n}|}-1
\ddot{s}_{\overline{n}|}=s_{\overline{n+1}|}-1
a_{\overline{n}|}=\frac{1-v^n}{i}