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\lim_{n\to\infty}{n \choose k}p^k(1-p)^{n-k}=\frac{\lambda^k e^{-\lambda}}{k!}
a_1=1\ ,\ \ a_n=a_{n-1}+n!\cdot n\ \ \ (n\ge2)
\alpha\in\mathbb{R},n\in\mathbb{Z}_{>0}
K[x]