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-log_{10}Ka=-log_{10}[H^ ]-log_{10}\frac{[A^-]}{[HA]}
pH=pKa log_{10}\frac{[A^-]}{[HA]}
Ka=\frac{[H^ ][A^-]}{[HA]}
x_{n 1}=y_n ax_n-\frac{5}{x_n^2 1} 6 0.2\exp(-y_n^2)
y_{n 1}=-bx_n