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az^2 bz c=0
z=x iy
Adenin
\purinev{4==NH$\mathrm{_2}$;6==H;2==H;1==H}
-log_{10}Ka=-log_{10}[H^ ]-log_{10}\frac{[A^-]}{[HA]}
pH=pKa log_{10}\frac{[A^-]}{[HA]}