Share The Formula You Found

+Label +Description

Recently Referred Formulae

a_{n+1}=3a_n -2
(1,2,4,8,16,...)
a_n=a_1+2(n-1)=1+2(n-1)=2n-1
\alpha=\beta
\sum_{k=1}^n(k-\frac{1}{2})