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p_{[a-*]}=p_a+\sum_{n\neq a} p_n \frac{p_a}{1-p_n}
289x^2-529
\sum_{n\neq a} p_n\frac{p_a}{1-p_n}
d_n -d_{n-1} = (2n+1)\frac{1}{2}\log\frac{1+1/(2n+1)}{1-1/(2n+1)}-1
a^2+2ab+b^2=(a+b)^2