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\sum_{n\neq a} p_n\frac{p_a}{1-p_n}=p_n\frac{p_a}{1-p_n}
\sum_{n\neq a} p_n\frac{p_a}{1-p_n}=
\sum_{n\neq a} p_n\frac{p_a}{1-p_n}==
p\sum_{n\neq a} p_n \frac{p_a}{1-p_n}
\sum_{n\neq a} p_n \frac{p_a}{1-p_n}