U_{\alpha}\cap U_{\beta}\neq \emptyset,\ x\in U_{\alpha}\cap U_{\beta},\ \varphi_{\alpha} (x)\in \partial \mathbf{H}\Longrightarrow \varphi_{\beta}(x)\in \partial \mathbf{H}
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Recent Referers:
  1. http://formula.s21g.com/?U_%7B%5Calpha%7D%5Ccap%20U_%7B%5...
  2. https://mkprob.hatenablog.com/entry/20120107/1325941401
  3. https://mkprob.hatenablog.com/
  4. http://formula.s21g.com/
  5. http://mkprob.hatenablog.com/