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Recently Referred Formulae

v=\sqrt{3}\times9.8
0=19.6t-\frac{1}{2}\times9.8t^2
t>0\therefore t=4.0
E[\phi(\overline{X}_n)]=1-\alpha
\left(\overline{X}_n - \displaystyle\frac{\tilde{\sigma}_n}{\sqrt{n}}t(n-1;\alpha / 2), \quad\overline{X}_n + \displaystyle\frac{\tilde{\sigma}_n}{\sqrt{n}}t(n-1;\alpha / 2)\right)\\