f({\bf x}|{\bf \theta})=\displaystyle\frac{1}{2\pi^{n/2}\{\det(\Sigma)\}^{1/2}}\exp\left\{-\frac{1}{2}\ ^t({\bf x}-{\bf \mu})\Sigma^{-1}({\bf x}-{\bf \mu})\right\} .png&_sm_nck=1
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Recent Referers:
  1. http://aaaazzzz036.hatenablog.com/entry/2013/05/11/010046