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Recently Referred Formulae

_{f|}a_{\overline{n}|}=v^f \cdot a_{\overline{n}|}
_{f|}\ddot{a}_{\overline{n}|}=\ddot{a}_{\overline{n+f}|}-\ddot{a}_{\overline{n}|}

x = y
{}_{x=2y}

f(x)=\frac{1}{x}