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a_{n+1}/a_n=2
a_{n+1}=-a_n\ \ \ \ \ (a_n)=(a_1,a_2,a_3,a_4,..)
a_{n+1}-1=3(a_n -1)=3^{n}(a_1-1)=3^{n+1}(a_0-1)
a_n=a_1+(n-1)n+(n-1)=1+(n-1)(n+1)=1+n^2-1=n^2
a_2-a_1=3,\ a_3-a_2=5,\ a_4-a_3=7,...